Csharp/C Sharp/XML LINQ/XPath

Материал из .Net Framework эксперт
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Querying XML with XPath Syntax

<source lang="csharp"> using System; using System.IO; using System.Linq; using System.Collections; using System.Collections.Generic; using System.Xml; using System.Xml.XPath; using System.Xml.Schema; using System.Xml.Linq; public class MainClass {

   public static void Main() {
       XDocument xDocument = new XDocument(
         new XElement("Books",
           new XElement("Book",
             new XAttribute("type", "Author"),
             new XElement("FirstName", "A"),
             new XElement("LastName", "B")),
          new XElement("Book",
             new XAttribute("type", "Author"),
             new XElement("FirstName", "C"),
             new XElement("LastName", "D"))));
       XElement bookParticipant = xDocument.XPathSelectElement("//Books/Book[FirstName="A"]");
       Console.WriteLine(bookParticipant);
   }

}

</source>


Select tags by name

<source lang="csharp"> using System; using System.Linq; using System.Collections; using System.Collections.Generic; using System.Xml; using System.Xml.Linq; public class MainClass {

   public static void Main() {
       XDocument xDocument = new XDocument(
         new XElement("Books",
          new XElement("Book",
            new XAttribute("type", "Author"),
            new XElement("FirstName", "J"),
            new XElement("LastName", "R")),
            new XElement("Book",
            new XAttribute("type", "Author"),
          new XElement("FirstName", "E"),
            new XElement("LastName", "B"))));
       IEnumerable<XElement> elements = xDocument.Element("Books").Elements("Book");
       foreach (XElement element in elements) {
           Console.WriteLine("Source element: {0} : value= {1}", element.Name, element.Value);
       }
       foreach (XElement element in elements.ToArray()) {
           Console.WriteLine("Removing {0}= {1} ¡�", element.Name, element.Value);
           element.Remove();
       }
       Console.WriteLine(xDocument);
   }

}

</source>