ASP.NET Tutorial/HTML Controls/File upload — различия между версиями

Материал из .Net Framework эксперт
Перейти к: навигация, поиск
м (1 версия)
 
м (1 версия)
 
(нет различий)

Текущая версия на 12:00, 26 мая 2010

input type="file"

<script language="C#" runat="server">
protected void PhotoSubmit(object o, EventArgs e) {
    if(thePhoto.PostedFile != null) {
        try {
            string filepath = "C:\\temp\\" + DateTime.Now.Ticks.ToString();
            thePhoto.PostedFile.SaveAs(filepath);
            status.Text = "File saved as " + filepath;
            
        }
        catch (Exception exc) {
            status.Text = "An Error occurred processing the file.  Please try again." + exc.ToString();
        }
    }
}
</script>
<form runat="server" enctype="multipart/form-data">
Please select an image to submit: <input id="thePhoto" type="file" runat="server"><br />
<input type="button" runat="server" value="Proceed" OnServerClick="PhotoSubmit" />
<asp:label runat="server" id="status" />
</form>


PostedFile.SaveAs

<%@ Page Language="C#" %>
<script runat="server">
void UploadButton_Click(Object sender, EventArgs e) {
    if(FileInput.PostedFile != null)
        {
            try
            {
                FileInput.PostedFile.SaveAs("c:\\test.txt");
            }
            catch (Exception exc)
            {
                Response.Write(exc.Message);
            }
        }
    }
</script>
<html>
  <head>
  </head>
  <body>
    <form id="Form1" method="post" enctype="multipart/form-data" runat="server">
        <input id="FileInput" type="file" runat="server" />
        <asp:Button id="UploadButton" onclick="UploadButton_Click" runat="server" Text="Upload"></asp:Button>
    </form>
  </body>
</html>


Use the HtmlInputFile control.

<%@ Page language="C#"%>
<%@ Import Namespace="System.IO" %>
<script runat="server">
    void UploadButton_Click(object sender, EventArgs e)
    {
        string savePath = @"c:\";
        if (!Directory.Exists(savePath)) {
          string msg = "<h1>The upload path doesn"t exist: {0}</h1>";
            Response.Write(String.Format(msg, savePath));
            Response.End();
        }
        if (FileUpload1.PostedFile != null)
        {
            string fileName = Path.GetFileName(FileUpload1.Value);
            savePath += fileName;
          FileUpload1.PostedFile.SaveAs(savePath);
            UploadStatusLabel.InnerText = "File saved as: <i>" + savePath + "</i>";
        }
        else
        {
            UploadStatusLabel.InnerText = "You did not specify a file to upload.";
        }
    }
</script>
<html xmlns="http://www.w3.org/1999/xhtml">
<head runat="server">
    <title>HtmlInputFile</title>
</head>
<body>
    <div id="pageContent">
        <form ID="Form1" runat="server">
          <h3>Select a picture to upload:</h3>
            <hr />
            <b>Picture to upload</b><br />
            <input type="file" id="FileUpload1" runat="server" />
            <br /><br />
            <input runat="server" id="UploadButton" type="submit" value="Upload" 
                onserverclick="UploadButton_Click" />
            <hr />
           <span runat="server" id="UploadStatusLabel" />
       </form>
    </div>
</body>
</html>
Источник — «http://nfex.ru/index.php?title=ASP.NET_Tutorial/HTML_Controls/File_upload&oldid=3279»